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c =2,997924 x108 m/s

 

 

h = 6,62606 × 10-34 kg m2 / sec

 

 

π = 3,141592...

 

 

2π = 6,283185

 

 

c2 =8,98755 x1016

 

 

μο = 4π × 10-7 H/m

 

 

εο=1/36π 109 F/m

 

 

μο/εο =zo =μο c

 

 

c = 1 / √ μο εο

 

 

c2 = 1 / μο εο

 

 

Ε = h f = hc / λ

 

 

Εo = m c2 = F λ

 

 

Fη = k q1 q2 / r2  

 

 

c=120π /4π ×10-7  

 

 

zo=120π   

 

 

c / h =fmax  

 

 

 c = fmax λmin

 

 

 c = amax tmin

 

 

c = zo / μ

 

 

 fmax=Vmax /λmin

 

 

Fmax=Emax /λmin

 

 

  λmin = c2 /amax

 

 

  amax = c2 / λmin

 

 

amax=λmin fmax2

 

 

Emax=Fmax λmin

 

 

 Emax = fmax h

 

 

Henry Farad =sec2

 

 

e=1,602176 ×10-19

 

 

√2 = 1,4142135

 

 

0,452444 x1042

 

 

1,35639 x1050 

 

 

1,23559 x1020

 

 

 

2,26873 x1023

 

 

 

h / c λmin = Mmax

 

 

 

Vmax = Mmax V / M

 

 

 

h c  / λ = Mpl G / λ

 

 

 

 

λe / re 2π = c / Vκ

 

 

 

 

1rad / s ~ 0,1591 Hz

 

 

 

 

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(

The logic transcended fantasy !

 

)

 

The revelation about the role of matter for the complex things and the instructive observations for the research begins in the moment, where we will think about a Universe complete within interval of a Maximum Period. With theoretical observations and with a sequence of reasoning, we can think more details and observe:

1) The finite space corresponds in the complete universe which is not present (in relative to the material world).

2) The free space is with a limit of longest distance (of removal), same for the all things (= a finite non-Euclidean geometry space).

3) The limit in the increase of length and in the longest distance (of removal) signals a limit of a minimal curvature. Respectively, the limit of a minimal length signals a limit for the increased curvature.

4) The finite space offers simultaneously two limits: in removal and approach.

5) The distance in the free space is also distance in time (because inevitably, the distance takes a time to travel).

6) The limit in the increase of length, given that a superior speed exists in motion, is also a limit in the maximum time of an interaction. The limit of minimal length also signals a limit for the minimal time of interaction.

7) The (empty) free space dynamical is connected also with structural elements (with mathematical relations), because the free space identified with a constant quantity of energy, while the structural elements with fluctuations of this constant energy.

8) The relation of finite space with the structure of matter is direct, simultaneous for the total of matter and its behavior is wave. A permanent relation exists between visible mass with invisible wave changes, and at a part these wave phenomena include the known electro­magnetic phenomena.

9) The isotropic relation of free space with the material things, after does not exist an absolute beginning and termination in its finite length.

10) The energy of the free space is found in balanced situation and when is disturbed, then this balance can comes back in the minimal time. (After of first calculations: minimal inertia Mmin = 0,737248 ×10-50 kg·s).

11) A fluctuation of energy is caused when the energy is transmitted (wave and oscillation).

12) The tendency of space to transmit energy in order to it compensates (counterbalance) the points where the energy is decreased.

13) The presence of matter and particles are considered as moments in the change of energy of the free space, and is owed in conditions where the substitution (compensation) in energy is prevented or becomes belatedly. (The flow impeded and delayed).

14) The structural elements ...>

1986 ~ 2010

 

Already from the 20th century have been ex­pressed thoughts about the decisive role of the free space in the structure of matter. From modern re­search, clues and paradoxical phe­nomena had multi­plied and certain physicists reco­gnized the im­passe of a physical interpre­tation on the structure of matter, if we had begin from se­parate particles. However, their these advanced thoughts, resear­chers made with full weak­ness to interpret the pre­sence of the free space, tran­sferring again the problem about the creation of matter in order to is solved in unknown future, with rocket a hope! They think evaluating their infor­mation of modern re­search, without they interpret, even in general, how itself the free space participates in shaping for the structure of matter, how attri­butes of the free space are result, how different phe­nomena are pro­duced by chan­ges in certain funda­mental re­lations as trans­formations by a common quantity of ener­gy. Their contri­bution for the re­search would be more useful and original, even if they ad­vanced in the solution of the pro­blem with formu­lation of right questions, leastwise in the case if was not possible to ad­vance with mathe­matical langu­age.

 

 

 

 

 

 

 

 

(

 

 

)

 

 

WHY THE CENTRAL IDEA OF THE "BIG BANG" THEORY IS THE BIGGEST FOOLISHNESS IN SCIENCE !  READ HERE

 

ENTRY FOR PHYSICISTS

Interpretation & Math investigation

 

 

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SHORT ANSWERS - BIG SURPRISES !

 

 

 

κοσμολογία, cosmology, in German: Kosmologie, in Italian and Portuguese: cosmologia, in France: cosmologie, in Spanish: cosmología, in Russian: космология, in Chinese: 宇宙论, in Hindi: ब्रह्मांड विज्ञान (), in Turkish: kozmoloji, in Swedish and Norwegian: kosmologi, in Arabic: الكوزمولوجيا علم الكونيات , in Hebrew: קוסמולוגיה

φιλοσοφία, philosophy, in German: Philosophie, in Italian and Portuguese: filosofia, in France: philosophie, in Spanish: filosofía, in Russian: философию, in Chinese: 哲学, in Hindi: दर्शन (tattvadnyaan), in Turkish: felsefe, in Swedish and Norwegian: filosofi, in Arabic: الفلسفة , in Hebrew: פילוסופיה

 on 2021-01-16.

 

G = 6,6725 ×10-11 m3 kg-1 s-2

 

 

M=E/c2 = h / f λ2

 

 

   M = h f μο εο

 

 

V = S / t

 

 

  p = M V = E / V

 

 

aκ = V2 / r

 

 

S = 1/2 a t2

 

 

g = G M / r2

 

 

F = M a

 

 

   a = V2 /λ = λ f2

 

 

V =√GM / r

 

 

Fg = G M1 M2 / r2

 

 

G=c2 / Smax

 

 

zo=50G /μο

 

 

Mmax=Fmax / amin

 

 

c2 / λmin = Gmax

 

 

   c2 = amax λmin  

 

 

   ω = 2 π f = V/ r

 

 

  2π = T Vκ / r 

 

 

  f =ω / 2π =V/2π r

 

 

λmax=amin Tmax2

 

 

 λmax = c2 /amin   

 

 

  amin = c / Tmax

 

 

   amax = c / Tmin

 

 

  c = h / M λ  

 

 

  M=m c / √c2- V2

 

 

L = M V r

 

 

0,73725 ×10-50

 

 

cos 90° = 0

 

 

c  G = 0,02

 

 

4,4929 x1018  

 

 

9,10938 ×10-31   

 

 

 

1,67262 ×10-27 

 

 

 

Mpl2 =h c / G

 

 

 

F r2 = M1M2 G

 

 

 

G = Fλ2 / Mpl2

 

 

 

 

DH / 1Mpc = c / VH

 

 

 

 

parsec~3,086x1016 m

 

 

 

 

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